Simplified Equilibria for Tests
Tearing mode test case in large aspect ratio ("intear")
- R0=10m, a=1m (circular cross-section)
- This should be sufficient to specify the test case:
rho = const = 1
T = 0.0497 - 0.0393 * PsiN
Btor = F0/R with F0=10
PsiN = a1*r + a2*r^2 + (1-a1-a2)*r^3 mit a1=-0.062829 und a2=1.84896
q = 1.71001 + 0.64087 PsiN + 1.81974 PsiN^2 - 2.49093 PsiN^3 + 2.29412 PsiN^4
Psi_axis = -0.20266
Psi_bnd = 0
n0 = 6*10^19 m^-3
rho0 = 2*10^-7 kg/m^3 -> sqrt(mu0 rho0)=5e-7 is the JOREK time normalization
- In cylinder approximation use:
Btor = 1andR = 10 - For the normalization of rho and T see here
- Details we need to agree about when comparing in detail: eta, visco, ZK_par, ZK_perp, D_perp, …